Note that, if you want to get the amount of columns of a table and you're using the "SHOW COLUMNS FROM $table" query, you will have to use mysql_num_rows() instead of mysql_num_fields() on the result. This becomes logical when thinking about it, because the SHOW COLUMNS query returns a result with six columns (Field, Type, Null, Key, Default and Extra) and with a single row for every column found. If you'd count the number of fields, you'd always get 6. If you count the number of rows, you'll get the amount of columns found.
mysql_num_fields
(PHP 4, PHP 5, PECL mysql:1.0)
mysql_num_fields — Zwraca liczbę pól w wyniku
Opis
int mysql_num_fields
( resource $wynik
)
mysql_num_fields() zwraca liczbę pól w wyniku.
Patrz także: mysql_select_db(), mysql_query(), mysql_fetch_field(), mysql_num_rows().
Aby zachować zgodność z poprzednimi wersjami, można użyć również mysql_numfields().
mysql_num_fields
php at jezusisheer dot nl
30-Mar-2007 09:10
30-Mar-2007 09:10
tharkey at tharkey dot net
19-Jun-2003 08:26
19-Jun-2003 08:26
You can use it without a requete, just to list the fields :
$liste_champs = mysql_list_fields ( $Base, $Table, $connexion);
for ($i=0; $i < mysql_num_fields ($l_champs); $i++) {
echo ( mysql_field_name ($l_champs, $i) );
echo (' / ');
}
apass AT passmoore DOT com
02-Oct-2002 12:52
02-Oct-2002 12:52
Adding to the last comment: you can dynamically loop through any number of columns AND rows like so-
$query="your SQL";
$result=mysql_query($query) or die("Query ($query) sucks!");
$fields=mysql_num_fields($result);
echo "<table>\n<tr>";
for ($i=0; $i < mysql_num_fields($result); $i++) //Table Header
{ print "<th>".mysql_field_name($result, $i)."</th>"; }
echo "</tr>\n";
while ($row = mysql_fetch_row($result)) { //Table body
echo "<tr>";
for ($f=0; $f < $fields; $f++) {
echo "<td>$row[$f]</td>"; }
echo "</tr>\n";}
echo "</table><p>";
This has been tested.
matt at iwdt dot net
24-Sep-2001 03:09
24-Sep-2001 03:09
here's one way to print out a row of <th> tags from a table
NOTE: i didn't test this
$result = mysql_query("select * from table");
for ($i = 0; $i < mysql_num_fields($result); $i++) {
print "<th>".mysql_field_name($result, $i)."</th>\n";
}
post a comment if there's an error
bwark at stanford dot edu
24-Dec-2000 11:56
24-Dec-2000 11:56
If you just want the number of fields in a table, you can do something like this:
--
$db_id = mysql_connet();
$result = mysql_query("DESCRIBE [tableName], $db_id);
$numFields = mysql_num_rows($result);
--
Because "DESCRIBE" returns one row for each field in the table (at least in MySQL), this will work.
dubious at 2xtreme dot net
13-Sep-2000 11:35
13-Sep-2000 11:35
Examples? How about this for a highly contrived but hopefully understandable example:
------------------------
<?php
function DoAQuery($Query)
{
$Result=mysql_db_query($Query);
$NumberOfFields=mysql_num_fields($Result);
print("There are $NumberOfFields Columns in the result<br>");
}
$ConnectionResource=mysql_connect("localhost","User","Password");
$Query="SELECT This, That, TheOther from Some_Table ORDER BY This";
DoAQuery($Query);
?>
-------------------------
Presuming I did that right, the entire output of this snippet should be "There are 3 Columns in the result" (assuming you actually have a mysql database with those fields, etc.) Presumably, in the Real World, you'd be using mysql_num_fields for formatting and such.
Hey, I SAID it was highly contrived, didn't I?
