zip_entry_filesize
If you want to get the real name of the file without the directory name, you can just use the function basename() as the follow:
<?
$zip_dir = "./import/";
$zip = zip_open($zip_dir."import.zip");
if ($zip) {
while ($zip_entry = zip_read($zip)) {
$file = basename(zip_entry_name($zip_entry));
$fp = fopen($zip_dir.basename($file), "w+");
if (zip_entry_open($zip, $zip_entry, "r")) {
$buf = zip_entry_read($zip_entry, zip_entry_filesize($zip_entry));
zip_entry_close($zip_entry);
}
fwrite($fp, $buf);
fclose($fp);
echo "The file ".$file." was extracted to dir ".$zip_dir."\n<br>";
}
zip_close($zip);
}
?>
Thefore you can extract files without concern with the directory that is set inside the zip source.
Remember to give write permission (w) on that directory.
Hello from Brazil.
Leandro
zip_entry_name
(PHP 4 >= 4.0.7, PHP 5 >= 5.2.0, PECL zip:1.0-1.9.0)
zip_entry_name — Retrieve the name of a directory entry
Opis
string zip_entry_name
( resource $zip_entry
)
Returns the name of the specified directory entry.
Zwracane wartości
The name of the directory entry.
add a note
User Contributed Noteszip_entry_name
leandro_dealmeida at hotmail dot com
27-Sep-2002 06:21
27-Sep-2002 06:21