Zmienne predefiniowane
@ben writes:
eval('global $' . join(',$', array_keys($GLOBALS)) . ';');
You may find extract($GLOBALS) useful. (also, note the optional EXTR_REFS flag)
Zasięg zmiennych
Zasięg zmiennej jest zależny od miejsca, w jakim została zdefiniowana. Najczęściej zmienne PHP widoczne są tylko w pojedynczym zasięgu. Taki zasięg rozciąga się na pliki dołączane funkcjami include() i require(). Na przykład:
$a = 1;
include "b.inc";
Tutaj zmienna $a będzie dostępna także w dołączonym pliku b.inc. Jednakże w funkcjach zdefiniowanych przez użytkownika zmienne mają zasięg lokalny. Każda zmienna użyta wewnątrz funkcji jest domyślnie ograniczona do zasięgu lokalnego, np.
$a = 1; /* zasięg globalny */
function Test()
{
echo $a; /* odwołanie do zmiennej o zasięgu lokalnym */
}
Test();
Ten skrypt nie wyświetli niczego, ponieważ instrukcja echo odwołuje się do zmiennej lokalnej $a, której jak dotąd nie została przypisana żadna wartość. Można tu zauważyć różnicę w stosunku do języka C, gdzie zmienne globalne są zawsze dostępne wewnątrz definicji funkcji, o ile nie zostały nadpisane przez lokalną definicję zmiennej. Może to spowodować taki problem, że ktoś może nieodwracalnie zmienić wartość zmiennej globalnej. W PHP zmienne globalne muszą być jawnie określone jako globalne wewnątrz funkcji, w której mają być użyte, do czego używamy słowa kluczowego global. Na przykład:
$a = 1;
$b = 2;
function Sum()
{
global $a, $b;
$b = $a + $b;
}
Sum();
echo $b;
Powyższy skrypt wyświetli wynik "3". Przez zadeklarowanie wewnątrz funkcji globalności zmiennych $a i $b, wszystkie odwołania do tych zmiennych będą odnosiły się do ich globalnych wersji. Nie ma żadnych ograniczeń w ilości zmiennych globalnych, na których chcemy operować wewnątrz funkcji.
Drugim sposobem uzyskania dostępu do zmiennych globalnych wewnątrz funkcji jest użycie specjalnej, zdefiniowanej przez PHP tablicy $GLOBALS. Powyższy przykład można zatem przepisać tak:
$a = 1;
$b = 2;
function Sum()
{
$GLOBALS["b"] = $GLOBALS["a"] + $GLOBALS["b"];
}
Sum();
echo $b;
$GLOBALS jest tablicą asocjacyjną, gdzie nazwa zmiennej jest kluczem, a zawartość zmiennej wartością komórki tablicy.
Jeszcze jedną ważną rzeczą, związaną z zasięgiem zmiennych jest zmienna statyczna (ang. static variable). Zmienna statyczna może mieć wyłącznie zasięg lokalny, ale nie traci swojej wartości, kiedy program opuści ten zasięg lokalny, w którym dana zmienna statyczna się znajduje. Proszę rozważyć poniższy przykład:
function Test ()
{
$a = 0;
echo $a;
$a++;
}
Ta funkcja jest bezużyteczna, gdyż przy każdym jej wywołaniu zmienna $a otrzymuje wartość 0, w związku z czym funkcja stale wyświetla "0". Występująca potem inkrementacja $a++ nie ma żadnego znaczenia, gdyż funkcja się kończy i zmienna $a znika. Aby powyższa funkcja miała jakiś sens, należy zapobiec gubieniu wartości $a, do czego używamy słowa kluczowego static:
function Test()
{
static $a = 0;
echo $a;
$a++;
}
Teraz, za każdym wywołaniem funkcji test, zostanie wyświetlona wartość zmiennej $a, po czym ta zmienna zostanie inkrementowana.
Zmienne statyczne pozwalają też na wykorzystanie funkcji rekurencyjnych, czyli takich, które wywołują same siebie. Funkcje rekurencyjne należy pisać ostrożnie, gdyż łatwo jest wywołać nieskończoną rekurencję. Musisz być pewny, że masz odpowiednie mechanizmy do zatrzymania rekurencji w pewnym momencie. Poniższa funkcja rekurencyjnie liczy do 10, używając zmiennej statycznej $licznik, aby wiedzieć, kiedy ma się zatrzymać:
function Test()
{
static $licznik = 0;
$licznik++;
echo $licznik;
if ($licznik < 10) {
Test ();
}
$licznik--;
}
add a note
User Contributed NotesZasięg zmiennych
tomodachi
31-Mar-2008 02:16
31-Mar-2008 02:16
ben FROM THE SITE younevercall.com
19-Mar-2008 10:40
19-Mar-2008 10:40
To make all globals available in a function:
eval('global $' . join(',$', array_keys($GLOBALS)) . ';');
Use with caution. "eval" is inherently dangerous.
Thomas
04-Mar-2008 11:06
04-Mar-2008 11:06
It might be worth noting in the article that you shouldn't define magic values at global level and use "global" to access them in a function - like I did in the past few years.
Use define() instead.
Anonymous
01-Mar-2008 08:10
01-Mar-2008 08:10
I was pondering a little something regarding caching classes within a function in order to prevent the need to initiate them multiple times and not clutter the caching function's class properties with more values.
I came here because I remembered something about references being lost. So I made a test to see if I could pull what I wanted to off anyway. Here's and example of how to get around the references lost issue. I hope it is helpful to someone else!
<?php
class test1{}
class test2{}
class test3{}
function cache( $class )
{
static $loaders = array();
$loaders[ $class ] = new $class();
var_dump( $loaders );
}
print '<pre>';
cache( 'test1' );
cache( 'test2' );
cache( 'test3' );
?>
kevin at metalaxe dot com
01-Mar-2008 07:56
01-Mar-2008 07:56
in reply to: "I hope some1 reading and understanding here creates an example about this. Im so lazy at doing that." -- pepesantillan at gmail dot com
Though not exactly your example, I don't like functions declared within functions. So this is, effectively, the same result you were explaining :P
<?php
ini_set( 'display_errors', true );
error_reporting( E_ALL | E_STRICT );
/**
* This is already in the global scope
**/
$global_var1 = 'I\'m global!';
// Call a function
some_function();
//Note that $localvar is NOT in the global scope
//Undefined variable Error
var_dump( $localvar );
function some_function()
{
/**
* Now we are in function scope. Global scope vars can't be accessed here
**/
// Undefined variable error (for $global_var1)
$localvar = $global_var1;
//Gonna call another function and send $localvar as ref
another_function( $localvar );
// Note that $localvar has a value here...
var_dump( $localvar );
}
function another_function( &$input )
{
// Get the global
global $global_var1;
// Assign it to $input which is referenced to $localvar in the other function
$input = $global_var1;
}
?>
Jeremy Skellington
30-Jan-2008 09:14
30-Jan-2008 09:14
Hmm, globals are a pretty poor solution and are pretty much forbidden in object oriented programming.
pepesantillan at gmail dot com
21-Dec-2007 03:36
21-Dec-2007 03:36
allan on 12-Sep-2006 10:53 wrote:
Using the global keyword inside a function to define a variable is essentially the same as passing the variable by reference as a parameter:
somefunction(){
global $var;
}
is the same as:
somefunction(& $a) {
}
The advantage to using the keyword is if you have a long list of variables needed by the function - you dont have to pass them every time you call the function.
---------------------------------------------------------------
Just wanted to point out that using global and using a reference is NOT the same. Why?
Imagine you just called the function somefunction() defined by out friend here from another function, say otherfunction().
If you use the global example (the 1st one), you will create a global variable $var for your whole php script.
But if you use the 2nd example where you reference a variable, you could be ONLY changing the value of some variable in the function that called the function somefunction() - in this case otherfunction() - and not creating a new global variable for your whole php script.
I hope some1 reading and understanding here creates an example about this. Im so lazy at doing that.
Hope you got the idea, and have as much fun learning to use php as I am! (yay! variables variables tutorial is next! xD)
jistanidiot at gmail dot com
19-Dec-2007 07:42
19-Dec-2007 07:42
Beware the problem that davo971 AT gmail DOT NO DAMN SPAM COM demonstrates can also happen in the following case:
index.php
<?php
include("test.inc");
?>
test.inc
<?php
function foo() {
global $bar;
echo $bar;
}
$bar = "Hello World";
foo();
?>
This prints nothing.
if you add global $bar at the start of test.inc it will work just fine.
SID TRIVEDI
27-Oct-2007 11:46
27-Oct-2007 11:46
<?php
/*
VARIABLE SCOPE : GLOBAL V/S STATIC
If variable $count is defined global as under, instead of static, it does not work well as desired in repeated function calls.
$count = 1; //if not defined STATIC, in each function call, it starts countig from one to 25.
global $count;
which gives folowing output:
0123456789101112131415161718192021222324
Total 24 numbers are printed.
So far 26 function call(s) made.
26272829303132333435363738394041424344454647484950
Total 50 numbers are printed.
So far 52 function call(s) made.
*/
function print_1to50()
{
// $count = 1;
// global $count;
static $count=1; // Initial assigment of One to $count, static declarion holds the last(previous) value of variable $count in each next function calls.
$limit = $count+24;
while($count<=$limit)
{
echo "$count";
$count=$count+1;
}
$num_count= $count-1;
echo "<br>\n". "Total $num_count numbers are printed.<br>";
return; // return statement without parenthesis()or arguments denotes end of a function rather than returning any values to subsequent function call(s).
} // end of while loop
$count=0;
print_1to50();
$count=$count+1;
print "So far $count function call(s) made.<br><br>";
print_1to50();
$count=$count+1;
print "So far $count function call(s) made.<br>";
/*
Which gives following output:
12345678910111213141516171819202122232425
Now I have printed 25 numbers.
I have made 1 function call(s).
26272829303132333435363738394041424344454647484950
Now I have printed 50 numbers.
I have made 2 function call(s).
*/
?>
daniel at nohair dot com
09-Sep-2007 10:01
09-Sep-2007 10:01
Ah, nested functions. Thanks for your notes below, search on page for "nested functions" folks. This is how this seems to work.
The child function is seen at global level only after they have been seen once. But, variables inside functions are only reachable within the functions scope.
<?php
$var1 = "This is \$var1 OUTSIDE parent function <br />";
function parent_function() {
echo "Now inside parent <br />";
$var1 = "This is \$var1 INSIDE parent function <br />";
$var2 = "This is \$var2 INSIDE parent function <br />";
function child_function() {
echo "now inside child <br />";
//global $var1; //Calls var1 outside parent_function;
echo $var1; //doesn't work without global;
// even if we comment out $var1 outside parent function.
// global $var1 doesn't reach the one inside parent function.
echo $var2; //doesn't work; Can't seem to reach parent variables.
}
echo "Now calling child<br />";
//child_function(); //works
}
// child_function(); //causes fatal error: call to undefined function;
parent_function(); //works;
child_function(); //now works;
?>
crack wilding
24-Aug-2007 05:04
24-Aug-2007 05:04
Another way of dealing with a large number of globals is to declare a single global array and then put all your global variables into it. Like this:
$_G = array(
'foo' => 'some text',
'bar' => 4,
'boo' => 'more text,
'far' => 'yet more text'
);
Now you just declare the one global array in each function:
function blah() {
global $_G;
echo $_G['foo']; // or whatever
}
You can freely add to it without having to go back and add variable declarations to your functions. Kinda like using the $GLOBALS superglobal, except you don't have to type so much.
mod
14-Mar-2007 08:03
14-Mar-2007 08:03
Can not access to global variables from destructor, if obj is not unseted at the end:
<?php
class A
{
function __destruct()
{
global $g_Obj;
echo "<br>#step 2: ";
var_dump($g_Obj);
}
function start()
{
global $g_Obj;
echo "<br>#step 1: ";
var_dump($g_Obj);
}
};
$g_Obj = new A(); // start here
$g_Obj->start();
$g_Obj = NULL; // !!! comment line and result will changed !!!
?>
Result, if line is not commented:
#step 1: object(A)#1 (0) { }
#step 2: object(A)#1 (0) { }
Result, if line is commented:
#step 1: object(A)#1 (0) { }
#step 2: NULL
12-Mar-2007 09:13
addendum to warhog at warhog dot net
about static variables within methods
<?php
class A
{
function incStaticVar()
{
static $var = 0;
$var++;
return $var;
}
}
class B extends A
{
}
$a =& new A();
$b =& new B();
print_r(array(
$a->incStaticVar(),
$b->incStaticVar(),
$a->incStaticVar(),
));
?>
expected result
Array
(
[0] => 1
[1] => 2
[2] => 3
)
real result
Array
(
[0] => 1
[1] => 1
[2] => 2
)
So I conclude that the PHP5 duplicates methods for each inherited classes.
Rohan
25-Jan-2007 07:11
25-Jan-2007 07:11
<?php
$a = 20;
function myfunction($b){
$a=30; //Local Variable
global $a,$c; //here global $a overrides the local
return $c=($b+$a);
}
print myfunction(40)+$c;
?>
The output of this function will be 120.
Michael
07-Nov-2006 07:35
07-Nov-2006 07:35
davo971 (http://us2.php.net/manual/en/language.variables.scope.php#69765), it seems you're encountering the same mental block that jason (http://us2.php.net/manual/en/language.variables.scope.php#65337) was having. I know how that goes, because I used to have this problem as well. Don't think of permission to access a variable as being transferred from function to function. There is exactly 1 global scope in any script, and that's the scope outside of all functions and classes. If you specify a variable as global, it does not mean you are accessing a variable in the calling function's namespace, it means you are accessing the variable in the global namespace. In your example, you seemed to think that declaring $new_var global in function2() would give it access to variables declared in function1()'s namespace. In fact, acess to variables does not propagate up the function stack--declaring you wish to work on a global variable ALWAYS gives you access to the SINGLE variable declared in the global namespace with that name. It's more easily understood when you work with the $GLOBALS array... there's only 1 such array, and consequently there's exactly 1 of each global variable. So if we modify your example to work correctly, here's what it'll look like:
<?php
$var = 'foo';
$new_var = 'asdf';
function function1()
{
global $new_var; //Now working with global $new_var, declared above
$new_var = 'bar'; //Changing $new_var from 'asdf' to 'bar'
function2();
}
function function2()
{
global $var, $new_var; //Accessing global variables $var and $new_var, declared outside any functions
echo($var . $new_var);
}
function1();
?>
Outputs foobar
davo971 AT gmail DOT NO DAMN SPAM COM
20-Sep-2006 07:17
20-Sep-2006 07:17
Be careful, come across this a lot.
<?php
$var = 'foo';
function function1()
{
global $var;
$new_var = 'bar';
function2();
}
function function2()
{
global $var, $new_var;
echo($var . $new_var);
}
function1();
?>
Outputs foo not foobar.
alan
12-Sep-2006 07:53
12-Sep-2006 07:53
Using the global keyword inside a function to define a variable is essentially the same as passing the variable by reference as a parameter:
somefunction(){
global $var;
}
is the same as:
somefunction(& $a) {
}
The advantage to using the keyword is if you have a long list of variables needed by the function - you dont have to pass them every time you call the function.
mega-squall at caramail dot com
22-Jul-2006 05:47
22-Jul-2006 05:47
In addition to sami's comment :
`static` keyword for class method is considered a compatibility feature in PHP5. In PHP6 however, calling an instance method (not defined using `static`) as a class method (using `class::method()` ) will display an EWarning. Also note that in PHP6, calling a class method (defined using `static`) as an instance method (using `$instance->method()`) will ALSO display an EWarning.
sami doesn't want spam at no-eff-eks com
21-Jul-2006 06:18
21-Jul-2006 06:18
PHP 5.1.4 doesn't seem to care about the static keyword. It doesn't let you use $this in a static method, but you can call class methods through an instance of the class using regular -> notation. You can also call instance methods as class methods through the class itself. The documentiation here is plain wrong.
class Foo {
public static function static_fun()
{
return "This is a class method!\n";
}
public function not_static_fun()
{
return "This is an instance method!\n";
}
}
echo '<pre>';
echo "From Foo:\n";
echo Foo::static_fun();
echo Foo::not_static_fun();
echo "\n";
echo "From \$foo = new Foo():\n";
$foo = new Foo();
echo $foo->static_fun();
echo $foo->not_static_fun();
echo '</pre>';
You'll see the following output:
From Foo:
This is a class method!
This is an instance method!
From $foo = new Foo():
This is a class method!
This is an instance method!
variable_scope-php dot net at fijiwebdesign dot com
07-Jul-2006 04:48
07-Jul-2006 04:48
In response to: Variable scope
Quote: "the global keyword *will* allow you to access variables in the global scope of your script, even if those variables were not made available locally to the parent function."
Actually, the "parent" function does not access a variable in its global scope unless it specifically uses the global modifier on the variable.
See this test:
<?php
$var = ''; // global scope
function foo() {
$var = 'Hello from $foo';
bar();
echo $var;
}
function bar() {
global $var;
$var = 'Hello from $var';
}
foo(); // prints: "Hello from $foo"
?>
The global scope of the variable $var is only available to bar(), not to foo(). Even if you were to put foo() and bar() in the same parent class, this would still be the case.
jason
29-Apr-2006 12:53
29-Apr-2006 12:53
This is probably self-evident to most folks here, and I expected this behavior, but it wasn't explicitly mentioned in the manual itself so I tested to find out: the global keyword *will* allow you to access variables in the global scope of your script, even if those variables were not made available locally to the parent function. In other words, the following will work as expected, even though $a is never referenced as global within the function foo:
<?php
function foo() {
bar();
}
function bar() {
global $a;
echo $a;
}
$a = "works!";
foo();
?>
Rhett
03-Apr-2006 10:37
03-Apr-2006 10:37
You could get around that:
<?php
function someFunction () {
static $isInitialized = 0;
static $otherStatic = 0; // or whatever default you want
if (!$isInitialized) {
$otherStatic = function(); // or whatever
$isInitialized = 1;
}
...
}
?>
Needs an extra variable and evaluates a condition every time it's run, but it does get around your problem.
SasQ
31-Mar-2006 11:02
31-Mar-2006 11:02
<?php
I use PHP 4.3 and it's impossible to assign a variable or function result to a static variable :-( Example:
function SomeFunction()
{
$LocalVar = 5;
static $MyStaticVar1 = some_function(); //ERROR
static $MyStaticVar2 = $LocalVar //ERROR
static $MyStaticVar3 = 7; //OK
return $MyStaticVar3++;
}
It's a little annoying, because in some cases the value of static variables aren't necessarily known at the moment of their initialisation. And sometimes it's required to be a value returned by some function or a value of some other function created earlier. Unfortunately, the moment of the initialization is the only moment, when this kind of assignment is possible to execute only on the first time the function is called.
?>
larax at o2 dot pl
23-Mar-2006 12:38
23-Mar-2006 12:38
About more complex situation using global variables..
Let's say we have two files:
a.php
<?php
function a() {
include("b.php");
}
a();
?>
b.php
<?php
$b = "something";
function b() {
global $b;
$b = "something new";
}
b();
echo $b;
?>
You could expect that this script will return "something new" but no, it will return "something". To make it working properly, you must add global keyword in $b definition, in above example it will be:
global $b;
$b = "something";
franp at free dot fr
11-Feb-2006 01:25
11-Feb-2006 01:25
If you want to access a table row using $GLOBALS, you must do it outside string delimiters or using curl braces :
$siteParams["siteName"] = "myweb";
function foo() {
$table = $GLOBALS["siteParams"]["siteName"]."articles"; // OK
echo $table; // output "mywebarticles"
$table = "{$GLOBALS["siteParams"]["siteName"]}articles"; // OK
echo $table; // output "mywebarticles"
$table = "$GLOBALS[siteParams][siteName]articles"; // Not OK
echo $table; // output "Array[siteName]article"
$result = mysql_query("UPDATE $table ...");
}
Or use global :
function foo() {
global $siteParams;
$table = "$siteParams[siteName]articles"; // OK
echo $table; // output "mywebarticles"
$result = mysql_query("UPDATE $table ...");
}
marcin
30-Dec-2005 06:07
30-Dec-2005 06:07
Sometimes in PHP 4 you need static variabiles in class. You can do it by referencing static variable in constructor to the class variable:
<?php
class test {
var $var;
var $static_var;
function test()
{
static $s;
$this->static_var =& $s;
}
}
$a=new test();
$a->static_var=4;
$a->var=4;
$b=new test();
echo $b->static_var; //this will output 4
echo $b->var; //this will output nul
?>
warhog at warhog dot net
13-Dec-2005 09:22
13-Dec-2005 09:22
Some interesting behavior (tested with PHP5), using the static-scope-keyword inside of class-methods.
<?php
class sample_class
{
public function func_having_static_var($x = NULL)
{
static $var = 0;
if ($x === NULL)
{ return $var; }
$var = $x;
}
}
$a = new sample_class();
$b = new sample_class();
echo $a->func_having_static_var()."\n";
echo $b->func_having_static_var()."\n";
// this will output (as expected):
// 0
// 0
$a->func_having_static_var(3);
echo $a->func_having_static_var()."\n";
echo $b->func_having_static_var()."\n";
// this will output:
// 3
// 3
// maybe you expected:
// 3
// 0
?>
One could expect "3 0" to be outputted, as you might think that $a->func_having_static_var(3); only alters the value of the static $var of the function "in" $a - but as the name says, these are class-methods. Having an object is just a collection of properties, the functions remain at the class. So if you declare a variable as static inside a function, it's static for the whole class and all of its instances, not for each object.
Maybe it's senseless to post that.. cause if you want to have the behaviour that I expected, you can simply use a variable of the object itself:
<?php
class sample_class
{ protected $var = 0;
function func($x = NULL)
{ $this->var = $x; }
} ?>
I believe that all normal-thinking people would never even try to make this work with the static-keyword, for those who try (like me), this note maybe helpfull.
zapakh at yahoo dot com
31-Oct-2005 05:23
31-Oct-2005 05:23
Addendum to the post by tc underline at gmx TLD ch, on unsetting global variables from inside functions:
If setting to null is not a suitable substitute for unset() in your application, you can unset the global variable's entry in the $GLOBALS superglobal.
<?php
function testc()
{
global $a;
echo " inner testc: $a\n";
unset($GLOBALS['a']);
echo " inner testc: $a\n";
}
$a = 5678;
echo "<pre>";
echo "outer: $a\n";
testc();
echo "outer: $a\n";
echo "</pre>\n";
?>
/***** Output:
outer: 5678
inner testc: 5678
inner testc: 5678
outer:
******/
If the behavior of testc (or testa or testb, for that matter) seems surprising, consider that the use of the 'global' keyword simply performs an assignment by reference. In other words,
<?php
global $a; //these two lines
$a =& $GLOBALS['a']; //are equivalent.
?>
If you've read http://php.net/references , then everything behaves as you'd expect.
tc underline at gmx TLD ch
14-Sep-2005 12:06
14-Sep-2005 12:06
Pay attention while unsetting variables inside functions:
<?php
$a = "1234";
echo "<pre>";
echo "outer: $a\n";
function testa()
{
global $a;
echo " inner testa: $a\n";
unset ($a);
echo " inner testa: $a\n";
}
function testb()
{
global $a;
echo " inner testb: $a\n";
$a = null;
echo " inner testb: $a\n";
}
testa();
echo "outer: $a\n";
testb();
echo "outer: $a\n";
echo "</pre>";
?>
/***** Result:
outer: 1234
inner testa: 1234
inner testa:
outer: 1234
inner testb: 1234
inner testb:
outer:
******/
Took me 1 hour to find out why my variable was still there after unsetting it ...
Thomas Candrian
thomas at pixtur dot de
08-Aug-2005 05:02
08-Aug-2005 05:02
Be careful with "require", "require_once" and "include" inside functions. Even if the included file seems to define global variables, they might not be defined as such.
consider those two files:
---index.php------------------------------
function foo() {
require_once("class_person.inc");
$person= new Person();
echo $person->my_flag; // should be true, but is undefined
}
foo();
---class_person.inc----------------------------
$seems_global=true;
class Person {
public $my_flag;
public function __construct() {
global $seems_global;
$my_flag= $seems_global
}
}
---------------------------------
The reason for this behavior is quiet obvious, once you figured it out. Sadly this might not be always as easy as in this example. A solution would be to add the line...
global $seems_global;
at the beginning of "class_person.inc". That makes sure you set the global-var.
best regards
tom
ps: bug search time approx. 1 hour.
www dot php dot net dot 2nd at mailfilter dot com dot ar
17-Jul-2005 03:43
17-Jul-2005 03:43
To the bemused poster: Of course you can't compare processing times between functions/no functions. I only wanted to see the difference between referenced and copied variables in different scenarios. Tests are only meant to compare between pairs (i.e., call a function with & and call the same function without &). I did 4 individual pairs of tests, so test 1 compares to test 2, test 3 compares to test 4, test 5 compares to test 6 and test 7 compares to test 8. The strlen() call was there only to make sure the value is actually accessed.
17-Jul-2005 02:42
To the last poster, regarding the speed tests:
<?php
$a = str_repeat('text', 100);
$b = $a;
$c =& $a;
// $c == $b == $a
// But you assigned a different value within the functions:
$len = strlen($a); // $len != $a
?>
I was bemused; how could the processing times of the functions/no-functions tests be compared in this way? And calling the strlen() function within each iteration of the loop must take more time anyway?
www dot php dot net dot 2nd at mailfilter dot com dot ar
16-Jul-2005 04:39
16-Jul-2005 04:39
I've been doing some performance tests. I thought I could squeeze some extra cyles using references, but I discovered they are more mysterious than I imagined (5.0.3).
Consider this:
$a = str_repeat('hola',10000000);
for($n = 0 ; $n < 1000000 ; $n++ ) { $b = $a; unset($b); }
real 0m1.514s
user 0m1.433s
sys 0m0.071s
The above times (as others in this note) are the best out of three attempts in an idle Linux box.
I expected the above to be a bit slow, since constructing $b might imply copying the 40MB string each time. It was very fast, though. Let's try with references:
$a = str_repeat('hola',10000000);
for($n = 0 ; $n < 1000000 ; $n++ ) { $b =& $a; unset($b); }
real 0m1.488s
user 0m1.380s
sys 0m0.071s
Not much of a gain, but it did took less time to complete. Will this work with functions? Let's see:
$a = str_repeat('hola',10000000);
for($n = 0 ; $n < 1000000 ; $n++ ) dosome($a);
function dosome($arg){ $t = strlen($arg); }
real 0m3.518s
user 0m3.276s
sys 0m0.088s
Mmm... much slower, but still pretty nice. I didn't use references yet, so let's try them out:
$a = str_repeat('hola',10000000);
for($n = 0 ; $n < 100 ; $n++ ) dosome($a);
function dosome(&$arg){ $t = strlen($arg); }
real 0m12.071s
user 0m6.190s
sys 0m5.821s
You think it is 3.5 times slower? Think again. It is 350,000 times slower. I had to limit the $n loop to 100 iterations in order to get those figures! I wonder what happens if I try to access the variable globally:
$a = str_repeat('hola',10000000);
for($n = 0 ; $n < 1000000 ; $n++ ) dosome();
function dosome(){ $t = strlen($GLOBALS['a']); }
real 0m3.007s
user 0m2.918s
sys 0m0.074s
Notice that using $GLOBALS we're back in bussiness. So using the global keyword should be exactly the same, isn't it? Wrong again:
$a = str_repeat('hola',10000000);
for($n = 0 ; $n < 100 ; $n++ ) dosome();
function dosome(){ global $a; $t = strlen($a); }
real 0m12.423s
user 0m6.112s
sys 0m5.917s
We're in the '350,000 times slower' domain again. I wonder why the script is spending so much time in sys.
A couple of additional tests to complete the puzzle:
$a = str_repeat('hola',10000000); $b = Array(&$a);
for($n = 0 ; $n < 100 ; $n++ ) dosome();
function dosome(){ $t = strlen($GLOBALS['b'][0]); }
real 0m12.087s
user 0m6.068s
sys 0m5.955s
$a = str_repeat('hola',10000000); $b = Array(&$a);
for($n = 0 ; $n < 100 ; $n++ ) dosome();
function dosome(){ global $b; $t = strlen($b[0]); }
real 0m12.158s
user 0m6.023s
sys 0m5.971s
I guess the $GLOBALS trick doesn't help when we access a reference stored in the global variable.
I'm completely confused, now. At this light, I will review my usage of the global keyword as well as for the references. I hope someone can benefit from this study too.
jameslee at cs dot nmt dot edu
16-Jun-2005 11:33
16-Jun-2005 11:33
It should be noted that a static variable inside a method is static across all instances of that class, i.e., all objects of that class share the same static variable. For example the code:
<?php
class test {
function z() {
static $n = 0;
$n++;
return $n;
}
}
$a =& new test();
$b =& new test();
print $a->z(); // prints 1, as it should
print $b->z(); // prints 2 because $a and $b have the same $n
?>
somewhat unexpectedly prints:
1
2
kouber at php dot net
28-Apr-2005 02:36
28-Apr-2005 02:36
If you need all your global variables available in a function, you can use this:
<?
function foo() {
extract($GLOBALS);
// here you have all global variables
}
?>
27-Apr-2005 01:46
Be careful if your static variable is an array and you return
one of it's elements: Other than a scalar variable, elements
of an array are returned as reference (regardless if you
didn't define them to be returned by reference).
<?php
function incr(&$int) {
return $int++;
}
function return_copyof_scalar() {
static $v;
if (!$v)
$v = 1;
return($v);
}
function return_copyof_arrayelement() {
static $v;
if (!$v) {
$v = array();
$v[0] = 1;
}
return($v[0]);
}
echo "scalar: ".
incr(return_copyof_scalar()).
incr(return_copyof_scalar()).
"\n";
echo "arrayelement: ".
incr(return_copyof_arrayelement()).
incr(return_copyof_arrayelement()).
"\n";
?>
Should print
scalar: 11
arrayelement: 11
but it prints:
scalar: 11
arrayelement: 12
as in the second case the arrays element was returned by
reference. According to a guy from the bug reports the
explanation for this behaviour should be somewhere here in
the documentation (in 'the part with title: "References with
global and static variables"'). Unfortunately I can't find
anything about that here. As the guys from the bug reports
are surely right in every case, maybe there is something
missing in the documentation. Sadly I don't have a good
explanation why this happens, so I decided to document at
least the behaviour.
vdephily at bluemetrix dot com
22-Apr-2005 11:51
22-Apr-2005 11:51
Be carefull about nested functions :
<?php
// won't work :
function foo1()
{
$who = "world";
function bar1()
{
global $who;
echo "Hello $who";
}
}
// will work :
function foo2()
{
$GLOBALS['who'] = "world";
function bar2()
{
global $who;
echo "Hello $who";
}
}
// also note, of course :
function foo3()
{
$GLOBALS['who'] = "world";
// won't work
echo "Hello $who";
// will work
global $who;
echo "Hello $who";
}
?>
S dot Radovanovic at TriMM dot nl
15-Feb-2005 04:50
15-Feb-2005 04:50
Sadly I have found out that I have been wrong about my statements below, why?
Well:
1. only the variables that were set in the constructor were 'live' in my referenced object
2. I was assigning this an object and not a reference
So:
I fixed nr. 1 by adding the & when initializing the object (this way this works on the initialized object and not a copy of it)
<?php
//screen factory
$objErrorConfig = & new Config("error.conf");
$objErrorConfig->setSection("messages");
//object factory
//If no file is stated, the last one is used, this way this instance will have the reference to the previously created instance of objErrorConfig in object screen
$objErrorConfig = & new Config();
$errorMessage = $objErrorConfig->get($errorName);
?>
Now the variables assigned after the constructor ($objErrorConfig->setSection("messages");) will also be 'live' in the static obj array.
I had to find a workaround for nr.2, since it is impossible to assign a reference to this. That's why I used code proposed by others, nl. I referenced all the members of the objects:
<?php
//Because we cannot make a direct reference from our object (by doing $this = & $theObject)
//we'll make references of our members
$arrClassVars = get_class_vars(get_class($theObject));
foreach($arrClassVars as $member=>$value) {
$this->$member = &$theObject->$member;
}
//To make sure we are working with a reference we will store our new object as the reference
//in the singeltonobject array (so all other initialized (referenced) objects will have the
//newest one as super referer
$arrSingletonObject[$this->_configfile] = & $this;
?>
So in the end, I had better used what everbody was using (creating a Singleton through an method, instead of through the constructor), but hey, I learned something again :)
S dot Radovanovic at trimm dot nl
05-Feb-2005 11:54
05-Feb-2005 11:54
To use the Singleton Pattern (as available in PHP5), we must do a little trick in PHP4.
Most examples I've seen look like this:
//Creation of singleton, Example, Example1 objects
//and then
<?
$myExample =& singleton('Example');
$myExample1 =& singleton('Example1');
?>
What I wanted was a way to use the Singleton Pattern on initialization of a new object (no calling of a method by reference (or something like that)).
The initializor doesn't have to know that the object it is trying to initialize uses the Singleton Pattern.
Therefor I came up with the following:
Beneath is part of a Config object that allows me to retrieve configuration data read from specific ini files (through parse_ini_file). Because I wanted to use the Config object in different other objects without having to pass a reference to the Config object all the time and without some of them having to now how the Config object was loaded (which configuration file was used) I had the need for the Singleton pattern.
To accomplish the Singleton pattern in the Constructor I've created a static array containing references to configuration file specific objects (each new configuration file creates a new instance of the Config object).
If we then try to create a new instance of an already loaded Config object (with the same configuration file), the objects set this to the reference of the previously created object, thus pointing both instances to the same object.
Here's the main part of the script.
Here's an example of how to use the Config object:
<?php
//dataheader
Config::setIniPath("/home/mydir/data/conffiles");
//object screen
$objTemplateConfig = new Config("template.conf");
$objErrorConfig = new Config("error.conf");
//objTemplateConfig and objErrorConfig are 2 different instances
$templatePath = $objTemplateConfig->get("template_path");
$errorColor = $objErrorConfig->get("error_color");
//object factory
//If no file is stated, the last one is used, this way this instance will have the reference to the previously created instance of objErrorConfig in object screen
$objErrorConfig = new Config();
$errorMessage = $objErrorConfig->get($errorName);
?>
So without the initializor knowing it he/she has retrieved a reference to a previously instantiated Config object (knowledge of this resides with the object).
Here's the constructor part of the config object:
S dot Radovanovic at trimm dot nl
05-Feb-2005 11:54
05-Feb-2005 11:54
<?php
function __constructor($configfile = '', $blnSingleton = true) {
//We must define a static array that contains our reference(s) to the object(s)
static $arrSingletonObject = array();
//We also need to specify a static local member, that keeps track of the last
//initialize configfile, so that we can use this if no file has been specified
//(this way we enable it for the initializor, to work with a previously initialized
//config object, without knowing what configfile it uses
static $lastConfigfile;
if(!empty($configfile)) {
//Store the set configfile name in the static local member
$lastConfigfile = $configfile;
} else if(!empty($lastConfigfile)) {
//If the configfile was empty, we retrieve it from the last known initialized
$configfile = $lastConfigfile;
} else {
//if we've reached so far, it means no configfile has been set at all (now
//or previously), so we cannot continue
trigger_error("No configfile has been specified.", ERROR);
//Return (instead of an exit (or die)) so that the constructor isn't continued
return;
}
//Set the configuration file
$this->_configfile = $configfile;
//Only if we want to use singleton we may proceed
if($blnSingleton) {
//We must now check to see if we already have a reference to the (to be created) config
//object
if(!isset($arrSingletonObject[$this->_configfile])) {
//Create of reference of myself, so that it can be added to the singleton object array
$arrSingletonObject[$this->_configfile] = &$this;
//We can now proceed and read the contents of the specified ini file
$this->_parseIniFile();
} else {
//Associate myself with the reference of the existing config object
$this = $arrSingletonObject[$this->_configfile];
}
}
}
?>
pulstar at ig dot com dot br
09-Sep-2004 03:02
09-Sep-2004 03:02
If you need all your global variables available in a function, you can use this:
<?php
function foo(parameters) {
if(version_compare(phpversion(),"4.3.0")>=0) {
foreach($GLOBALS as $arraykey=>$arrayvalue) {
global $$arraykey;
}
}
// now all global variables are locally available...
}
?>
info AT SyPlex DOT net
01-Sep-2004 02:35
01-Sep-2004 02:35
Some times you need to access the same static in more than one function. There is an easy way to solve this problem:
<?php
// We need a way to get a reference of our static
function &getStatic() {
static $staticVar;
return $staticVar;
}
// Now we can access the static in any method by using it's reference
function fooCount() {
$ref2static = & getStatic();
echo $ref2static++;
}
fooCount(); // 0
fooCount(); // 1
fooCount(); // 2
?>
shyam dot g at gmail dot com
03-Jul-2004 12:52
03-Jul-2004 12:52
in response to Michael's comments, it is imperative to observe that static variables in methods of an object are not class level variables.
and since both a and b from the previous example are 2 different objects, there is no question of the static variable being shared between the objects.
The variable is static with respect to the function and not the class.
sam
Michael Bailey (jinxidoru at byu dot net)
04-Jun-2004 08:43
04-Jun-2004 08:43
Static variables do not hold through inheritance. Let class A have a function Z with a static variable. Let class B extend class A in which function Z is not overwritten. Two static variables will be created, one for class A and one for class B.
Look at this example:
<?php
class A {
function Z() {
static $count = 0;
printf("%s: %d\n", get_class($this), ++$count);
}
}
class B extends A {}
$a = new A();
$b = new B();
$a->Z();
$a->Z();
$b->Z();
$a->Z();
?>
This code returns:
A: 1
A: 2
B: 1
A: 3
As you can see, class A and B are using different static variables even though the same function was being used.
Randolpho
02-Apr-2004 10:53
02-Apr-2004 10:53
More on static variables:
My first not is probably intuitive to most, but I didn't notice it mentioned explicitly, so I'll mention it: a static variable does not retain it's value after the script's execution. Don't count on it being available from one page request to the next; you'll have to use a database for that.
Second, here's a good pattern to use for declaring a static variable based on some complex logic:
<?
function buildStaticVariable()
{
$foo = null;
// some complex expression or set of
// expressions/statements to build
// the return variable.
return $foo;
}
function functionWhichUsesStaticVar()
{
static $foo = null;
if($foo === null) $foo = buildStaticVariable();
// the rest of your code goes here.
}
?>
Using such a pattern allows you to separate the code that creates your default static variable value from the function that uses it. Easier to maintain code is good. :)
jmarbas at hotmail dot com
17-Jan-2004 12:34
17-Jan-2004 12:34
Whats good for the goose is not always good for the iterative gander. If you declare and initialize the static variable more than once inside a function ie.
function Test(){
static $count = 0;
static $count = 1;
static $count = 2;
echo $count;
}
the variable will take the value of the last declaration. In this case $count=2.
But! however when you make that function recursive ie.
function Test(){
static $count = 0;
static $count = 1;
static $count = 2;
$count++;
echo $count;
if ($count<10){
Test();
}
}
Every call to the function Test() is a differenct SCOPE and therefore the static declarations and initializations are NOT executed again. So what Im trying to say is that its OK to declare and initialize a static variable multiple times if you are in one function... but its NOT OK to declare and initialize a static variable multiple times if you call that same function multiple times. In other words the static variable is set once you LEAVE a function (even if you go back into that very same function).
Jack at soinsincere dot com
14-Nov-2003 07:11
14-Nov-2003 07:11
Alright, so you can't set a static variable with a reference.
However, you can set a static variable to an array with an element that is a reference:
<?php
class myReference {
function getOrSet($array = null) {
static $myValue;
if (!$array) {
return $myValue[0]; //Return reference in array
}
$myValue = $array; //Set static variable with array
static $myValue;
}
}
$static = "Dummy";
$dummy = new myReference;
$dummy->getOrSet(array(&$static));
$static = "Test";
print $dummy->getOrSet();
?>
flobee at gmx dot net
06-Nov-2003 09:26
06-Nov-2003 09:26
i found out that on any (still not found) reason the <?php static $val =NULL; ?> is not working when trying to extract the data form the $var with a while statment
e.g.:
<?php
funktion get_data() {
static $myarray = null;
if($myarray == NULL) {
//get some info in an array();
$myarray = array('one','two');
}
while(list($key,$val) = each( $myarray ) ) {
// do something
echo "x: $key , y: $val";
}
}
?>
when using foreach($myarray AS $key => $val) { .... instad of while then i see the result!
ppo at beeznest dot net
09-Jul-2003 03:59
09-Jul-2003 03:59
Even if an included file return a value using return(), it's still sharing the same scope as the caller script!
<?php
$foo = 'aaa';
$bar = include('include.php');
echo($foo.' / '.$bar);
?>
where include.php is
<?php
$foo = 'bbb';
return $foo;
?>
The output is: bbb / bbb
Not: aaa / bbb
j at superjonas dot de
14-Mar-2003 07:08
14-Mar-2003 07:08
> pim wrote:
> in addition:
> if you define a function in that included file, it can't get
> the variables from the inluded file's scope. global won't work.
> The only way to give such an include function access to global
> vars is via arguments. I don't know if this is a bug in PHP.
>
> //---- from within function included file -----
> echo $var1; // this one works
> function foo()
> {
> global $var1;
> echo $var1; // this one doesn't
> }
It works if you additionally declare the variables from the inluded file's scope as global.
example:
<?php
/* file1.php */
function func1() {
include("file2.php");
func2();
}
func1();
?>
<?php
/* file2.php */
global $var; // declare as global here
$var = 'something';
function func2() {
global $var; // again here
echo $var; // prints "something"
}
?>
ben-xo aatt dubplates.org
13-Mar-2003 07:05
13-Mar-2003 07:05
regarding the above "unset" example: I quote from the manual page for "unset".
"If a static variable is unset() inside of a function, unset() destroyes the variable and all its references. "
As mentioned above, on this page, static vars are implemented as references. When you unset() a reference, what you are doing is deleting a particular name for that variable. In your example, you delete the LOCAL NAME $a, but the static contents are still there (hidden) and next time you call your function, a NEW LOCAL NAME (again $a...) is linked to the SAME backing data.
Workaround would be something like "$a = null".
unset($a) is very much like $a = &null however, which, if you read the notes above, won't have the desired affect on static or global variables.
04-Mar-2003 04:25
As far as I can see, it's not possible to unset() a static variable inside the function:
function Test($unset = false) {
static $a = 0;
echo $a++;
if ($unset) unset($a);
}
Test();
Test();
Test(true);
Test();
Test();
This will output 01234. I would expect it to at least show 01201.
pim at lingewoud dot nl
27-Feb-2003 08:46
27-Feb-2003 08:46
shevek wrote:
>> If you include a file from within a function using include(),
>> the included file inherits the function scope as its own
>> global scope, it will not be able to see top level globals
>> unless they are explicit in the function.
in addition:
if you define a function in that included file, it can't get the variables from the inluded file's scope. global won't work. The only way to give such an include function access to global vars is via arguments. I don't know if this is a bug in PHP.
//---- from within function included file -----
echo $var1; // this one works
function foo()
{
global $var1;
echo $var1; // this one doesn't
}
jg at nerd-boy dot net
08-Feb-2003 01:10
08-Feb-2003 01:10
It's possible to use a variable variable when specifying a variable as global in a function. That way your function can decide what global variable to access in run-time.
function func($varname)
{
global $$varname;
echo $$varname;
}
$hello = "hello world!";
func("hello");
This will print "hello world!", and is roughly the same as passing by reference, in the case when the variable you want to pass is global. The advantage over references is that they can't have default parameters. With the method above, you can do the following.
function func($varname = FALSE)
{
if ($varname === FALSE)
echo "No variable.";
else
{
global $$varname;
echo $$varname;
}
}
$hello = "hello world!";
func("hello"); // prints "hello world!"
func(); // prints "No variable."
wjs@sympaticoDOTca
10-Dec-2002 06:03
10-Dec-2002 06:03
Becareful where you define your global variables:
This will work:
<?php
$MyArray = array("Dog");
function SeeArray(){
global $MyArray;
if (in_array("Dog",$MyArray)){
foreach ($MyArray as $Element){
echo "$Element <hr/>";
}
}
}
SeeArray();
?>
while this will not:
<?php
SeeArray();
$MyArray = array("Dog");
function SeeArray(){
global $MyArray;
if (in_array("Dog",$MyArray)){ // an error will generate here
foreach ($MyArray as $Element){
echo "$Element <hr/>";
}
}
}
?>
jez at india dot com
31-Oct-2002 09:35
31-Oct-2002 09:35
If anyone needs a permanent array / hash, similar in functionality to ASP's application object, check out the article on
http://zez.org/article/articleview/46/1/
which has some working code (written by me) attached. This code implements a hash with application scope, i.e. its contents can be accessed from all php scripts running on the same computer. You could use it, for example, to globally cache configuration settings for a site.
The hash is also cached in the db, i.e. it's inviolable. Its contents are buffered in memory, so there's no hit on the db when accessing the hash apart from the first time you read it, and of course when you write to it.
mu at despammed dot com
16-Oct-2002 01:12
16-Oct-2002 01:12
morthanpurpl: You don't have to initialize variables you use first inside a variable, at least not in PHP4.2.2. The following will just work fine and output "iam":
<?php
function dumdum()
{
global $a;
$a = "iam";
}
dumdum();
echo $a;
?>
heatwave at fw dot hu
15-Oct-2002 02:12
15-Oct-2002 02:12
Some people (including me) had a problem with defining a long GLOBAL variable list in functions (very error prone). Here is a possible solution. My program parses php file for functions, and compiles GLOBAL variable lists. Then you can just remove from the list those variables which need not be global.
<?php
//parser for GLOBAL variable list
$pfile=file("myfile.php4");
for($i